Puzzles
Q1 . A man smokes a cigarette of length 6 cm (Butt size not included). It takes him 2 seconds to take one puff and his inhaling capacity burns 3 mm of cigarette in one puff. After taking a puff he rests for some time and takes another puff. Even if he does not smoke the air has the capacity to burn 1 mm in 1 second. He completes his cigarette in 30 seconds. How many puffs he takes in completing one cigarette. (Assume that he completes the cigarette with a complete puff)
{A}12
{B}15
{C}10
{D}None of the above.
{E}Cannot be determined.
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15 puffs !
Ans: {D} None of the above.
Explanation:
Lets assume that option {A} is correct. i.e 12 puffs.
Therefore total time taken for 12 puffs is 24 sec (2 sec = 1 puff) and the burn would be 12*3 = 36 mm of the cigratte.
Now for the remaining 6 sec (30 – 24), the air burns 6 mm of cigratte (1 sec = 1 mm burn)
Summing up the burns we get : 36 mm + 6 mm = 42 mm
But the cigratte length is 60 mm hence {A} is incorrect.
Similarly for {B} 15 puff
we get 45 mm of burn with nothing left for the air.(1 puff = 2 sec)
Similarly for {C} 10 puff
we get 30 mm of burn with puff and 10 mm of burn with air i.e 40mm
Although Durgendu is right to a certain extent, he over analyzed things like many programmers, the text doesn’t mention he takes more than 2 puffs!
“After taking a puff he rests for some time and takes another puff”.
So the real answer is he takes 2 puffs!
Oh and i forgot to mention that its impossible to complete a 6cm cigarette under 30 seconds. He can only take a maximum of 15 puffs at 3mm each which is still under 6cm.
Upon further analysis, lol. My answer is 15 IF a puff includes the passive 1mm burn time on top of the 3mm burn.
Cannot be determined
Analysis…
Smoker puffs in 2 secs ==> 3mm + 2 mm (Air) ==> 5mm burn
Rests for 1 sec ==> 1 mm burn
so in 3 secs… 6mm was burned…
repeat that 10 times ==> 30secs…
multiplying… 6mm by 10… i get 60mm….
Result… My answer would be {C}…
P.S.
Please inform me if I get it right… I would really appreciate an update on the topic and proove that all the analysis above were overly done…
Note: I think what everyone over annalyzed was the fact that during a 2sec puff, air could still affect the burn for every second of it… everyone did not count the 2mm burn during the puff accountable to air…
The text read… “Even if he does not smoke…” simply meant that whether he smoked or not, air would still burn the cigarette, as with in real life.
If I’m right with my analysis, that would remind me of what my English teacher, not my Math or Comp. Sci. Prof., would say… “We’ve got to read between the lines…”